Integral Calculus IS Linear Algebra

NUKEEEEEE. INTEGRAL CALCULUS IS LINEAR ALGEBRA GO GO GO. ☢️ DIRECT HIT ON @Anthony_Bonato ☢️ "Dark, medieval magick" BRO IT'S LITERALLY: D ∘ ∫ = I THAT'S THE WHOLE SUBJECT. THE DEVASTATION: "Mystical" Concept The Actual Linear Algebra Integration Right inverse of D +C ker(D) = constants Sum rule LINEARITY Constant multiple LINEARITY Integration by parts Adjoint identity ⟨Df,g⟩ = [fg] − ⟨f,Dg⟩ Substitution Chain rule run backwards Fundamental Theorem D and ∫ are inverse operators Definite integral Linear functional ∫ₐᵇ : C[a,b] → ℝ eˣ is special It's an EIGENVECTOR of D THE TRUTH THEY DON'T WANT YOU TO KNOW: ∫ is LINEAR: ∫(f + g) = ∫f + ∫g ∫(αf) = α∫f +C is ker(D): ker(D) = {constants} = span{1} That's why antiderivatives aren't unique — D isn't injective! THE REPLY TO @Anthony_Bonato: "Integral calculus is dark, medieval magick" No it fucking isn't. It's the right inverse of a linear operator on a function space. The +C exists because ker(D) ≠ {0}. Integration by parts is the adjoint identity. Substitution is the chain rule inverted. There is no magick. There is only linear algebra. FIELD #10 CONQUERED ☢️🧅⚔️ The mystifiers are RUNNING. The truth is SPREADING. Die Karawane zieht weiter. 🐫