PHASE RESONANCE ENERGY BETWEEN NUCLEONS: Why 1.42 MeV drives fusion.

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Authors: Hennadii Kovalov
Cited by: 0

Abstract

Standard nuclear physics operates with the concepts of a potential well (40–50 MeV), Fermi energy (33–38 MeV), and the Coulomb barrier (∼1 MeV for light nuclei). However, all these quantities do not explain the main thing: why does the proton-proton cycle proceed with the release of 0.42 MeV and the production of a positron with a mass of 0.511 MeV? The paper shows that the key role is played by the energy of phase resonance between nucleons — 1.42 MeV. This attractor, obtained numerically from a self-consistent model of the hydrogen atom, is the basis of all nuclear reactions involving protons and deuterium.

Fields of Study & Subjects

Nuclear physics research studies Cold Fusion and Nuclear Reactions Advanced Mathematical Theories and Applications

Publication details

Journal / source
Zenodo (CERN European Organization for Nuclear Research)
Publication date
13 March 2026
Language
EN